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思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
。夫子对此有专业解读
Friday evening is a great time for tinkering with a side project after a long week. You pour some tea, open your laptop and navigate to your project, only to find a red banner across whole app placed by the browser saying “Deceptive site ahead”.
Андрей Ставицкий (Редактор отдела «Наука и техника»)
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